Popcorn prediction

Prediction: Changing the appended value from 5 to 8 will output the list [6, 12, 12, 8] and a length of 4. Updating an existing index in place modifies the current value without changing the number of items, whereas appending adds a brand new slot at the end, increasing the total length of the list by 1.

Code Runner Challenge

popcorn C

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# CODE_RUNNER: popcorn C

level_stars = [6, 9, 12]
level_stars[1] = level_stars[1] + 3
level_stars.append(8)
print(level_stars)
print(len(level_stars))
Lines: 1 Characters: 0
Output
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MCQ

  1. B
  2. A
  3. C
  4. B

Code Runner Challenge

Homework

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# CODE_RUNNER: Homework

# --- Homework Hack · Grow Your UESL Game ---

# 1. Main Game State Run
print("--- Main Game Run ---")
level_stars = [12, 18, 10]  # Each element represents one level's collected stars in level order

# Safely add 5 to the second level only if a second level exists
if len(level_stars) >= 2:
    level_stars[1] += 5

# Append 7 for a new level
level_stars.append(7)

# Calculate total and level count using a traversal loop
total_stars = 0
for stars in level_stars:
    total_stars += stars

level_count = len(level_stars)

# Print results
print("Collection:", level_stars)
print("Level Count:", level_count)
print("Total Stars:", total_stars)


# 2. Edge Case Test: Empty List ([])
print("\n--- Empty List Test Case ---")
level_stars = []

# Skip the second-level update when there is no second element
if len(level_stars) >= 2:
    level_stars[1] += 5

total_stars = 0
for stars in level_stars:
    total_stars += stars

level_count = len(level_stars)

# Print results for empty state
print("Collection:", level_stars)
print("Level Count:", level_count)
print("Total Stars:", total_stars)
Lines: 1 Characters: 0
Output
Click "Run" in code control panel to see output ...